The 32 must-know formulas for weeks 1–4, on one page. Print it.
Q={pq∣p,q∈Z,q≠0}\mathbb{Q} = \left\{ \frac{p}{q} \mid p, q \in \mathbb{Z}, q \neq 0 \right\}Q={qp∣p,q∈Z,q=0}
2∈{1,2,3,4,6,8,12,24}2 \in \{1, 2, 3, 4, 6, 8, 12, 24\}2∈{1,2,3,4,6,8,12,24}
∣S∣|S|∣S∣
A⊆BA \subseteq BA⊆B
P(S)\mathcal{P}(S)P(S)
A∪BA \cup BA∪B
A∩BA \cap BA∩B
A∖BA \setminus BA∖B
R⊆A×BR \subseteq A \times BR⊆A×B
f:X→Yf: X \to Yf:X→Y
f is injective if f(x1)=f(x2)⇒x1=x2f \text{ is injective if } f(x_1) = f(x_2) \Rightarrow x_1 = x_2f is injective if f(x1)=f(x2)⇒x1=x2
f is surjective if ∀y∈Y,∃x∈X such that f(x)=yf \text{ is surjective if } \forall y \in Y, \exists x \in X \text{ such that } f(x) = yf is surjective if ∀y∈Y,∃x∈X such that f(x)=y
mn=x−x1x2−x\frac{m}{n} = \frac{x - x_1}{x_2 - x}nm=x2−xx−x1
mn=y−y1y2−y\frac{m}{n} = \frac{y - y_1}{y_2 - y}nm=y2−yy−y1
x=mx2+nx1m+n,y=my2+ny1m+nx = \frac{m x_2 + n x_1}{m + n}, \quad y = \frac{m y_2 + n y_1}{m + n}x=m+nmx2+nx1,y=m+nmy2+ny1
Atriangle=12∣x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣A_{\text{triangle}} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right|Atriangle=21∣x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣
y−y0=m(x−x0)y - y_0 = m(x - x_0)y−y0=m(x−x0)
x−3+y3=1\frac{x}{-3} + \frac{y}{3} = 1−3x+3y=1
xa+yb=1\frac{x}{a} + \frac{y}{b} = 1ax+by=1
m1=m2 ⟺ l1∥l2m_1 = m_2 \iff l_1 \parallel l_2m1=m2⟺l1∥l2
m1⋅m2=−1 ⟺ l1⊥l2m_1 \cdot m_2 = -1 \iff l_1 \perp l_2m1⋅m2=−1⟺l1⊥l2
a1b2=a2b1 ⟺ l1∥l2a_1 b_2 = a_2 b_1 \iff l_1 \parallel l_2a1b2=a2b1⟺l1∥l2
a1a2+b1b2=0 ⟺ l1⊥l2a_1 a_2 + b_1 b_2 = 0 \iff l_1 \perp l_2a1a2+b1b2=0⟺l1⊥l2
∣Ax1+By1+C∣A2+B2\frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}}A2+B2∣Ax1+By1+C∣
∣C1−C2∣A2+B2\frac{|C_1 - C_2|}{\sqrt{A^2 + B^2}}A2+B2∣C1−C2∣
SSE=∑i=1n(yi−mxi−c)2SSE = \sum_{i=1}^{n} (y_i - mx_i - c)^2SSE=∑i=1n(yi−mxi−c)2
g(x)=2ax+bg(x) = 2 a x + bg(x)=2ax+b
xvertex=−b2ax_{\text{vertex}} = -\frac{b}{2a}xvertex=−2ab
x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}x=2a−b±b2−4ac
p(x)+q(x)=∑k=0max(m,n)(ak+bk)xkp(x) + q(x) = \sum_{k=0}^{\max(m,n)} (a_k + b_k) x^kp(x)+q(x)=∑k=0max(m,n)(ak+bk)xk
p(x)−q(x)=∑k=0max(m,n)(ak−bk)xkp(x) - q(x) = \sum_{k=0}^{\max(m,n)} (a_k - b_k) x^kp(x)−q(x)=∑k=0max(m,n)(ak−bk)xk
p(x)⋅q(x)=∑k=0m+n(∑j=0kajbk−j)xkp(x) \cdot q(x) = \sum_{k=0}^{m+n} \left( \sum_{j=0}^{k} a_j b_{k-j} \right) x^kp(x)⋅q(x)=∑k=0m+n(∑j=0kajbk−j)xk
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